764
edits
Math:Resource Preservation: Difference between revisions
m
no edit summary
mNo edit summary |
mNo edit summary |
||
| Line 21: | Line 21: | ||
So the number of daggers produced is <math>120 + (120 \times 0.8) + (120 \times 0.8 \times 0.8) + ... + (120 \times 0.8^n)</math> where <math>n</math> is a number as huge as you can imagine. | So the number of daggers produced is <math>120 + (120 \times 0.8) + (120 \times 0.8 \times 0.8) + ... + (120 \times 0.8^n)</math> where <math>n</math> is a number as huge as you can imagine. | ||
If we replace the number <math>120</math> with any other number <math>a</math> and the probability 0.8 with any other probability <math>r</math>, the number of produced daggers would look like this: | If we replace the number <math>120</math> with any other number <math>a</math> and the probability <math>0.8</math> with any other probability <math>r</math>, the number of produced daggers would look like this: | ||
<math>a + (a \times r) + (a \times r \times r) + ... + (a \times r^n)</math> | <math>a + (a \times r) + (a \times r \times r) + ... + (a \times r^n)</math> | ||