Mastery: Difference between revisions

1 byte removed ,  18 February 2020
fixed floor
(Updated formula with math plugin, flagged for needing new table)
(fixed floor)
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\begin{cases}
\begin{cases}
0 & n=1 \\
0 & n=1 \\
\left \lfloor \sum_{i=1}^{n-1} \left \lfloor \frac{i+300(2^{\frac{i}{7}})}{48} \right \rfloor \right \rfloor & n\geq 2 \\
\left \lfloor \sum_{i=1}^{n-1}\frac{\left \lfloor i+300(2^{\frac{i}{7}}) \right \rfloor}{48} \right \rfloor & n\geq 2 \\
\end{cases}</math>
\end{cases}</math>